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VIS (SR3)
eleonora.capocasa - 12:05 Friday 21 September 2018 (6235) Print this report
Details about SR3 PreIsolator LVDT2EUL matrix computation

[Lucia, Enzo, Eleonora]

As a first step to perform the  PI horizontal LVDT diagonalization  we have updated the sensing matrix LVDT2EUL, as reported by Enzo in klog #6073

Here are reported some more details about the convention used and the matrix computation:

  1. x  and y are the interferometer global coordinates.
  2. The HR surface faces  +y  and identifies the longitudinal direction L.
  3. Transverse direction T is 90° anticlockwise from L ( - x in the IFO coordinates).
  4. Positive Yaw motion (Y) is anticlockwise.
  5. Leg 1 of the IP is along the +x direction and angles are measured anticlockwise from it. 
  6. The horizontal LVDs are numbered from H0 to H2 anticlockwise, staring form x axis and the positive direction of their axis is also taken anticlockwise.
  7. According to the CAD  (and visual inspection) they are separated by 120° and the first one is place at an angle alpha = 22.5° from the x axis.
  8. NOTE that in the initial sensing matrix this angle was taken to be 30° since it was measured considering the center of the LVDT+COIL unit. While it is more accurate to consider the position of the only LVDT (see first attaches picture of entry #6073)
 
According to the convention above, the projection of any horizontal motion of the Preisolator (with components L, T, Y)  on each horizontal LVDT is 
 
H_n =  L* cos (alpha + 2n*pi/3) + T *sin (alpha+ 2n*pi/3) + R_h*Y
 
where n goes from 0 to 2 and R_h is the distance from the LVDT to the PI center. 
 
Therefore, the matrix S connecting  EUL to LVDT   as   [H0 H1 H2] = S* [L T, Y] is 
 
    cos (alpha)                   sin(alpha)                     R_h
    cos (alpha + 2pi/3)      sin(alpha+ 2pi/3)          R_h
    cos (alpha + 4pi/3)      sin(alpha+ 4pi/3)          R_h
 
and the sensing matrix LVDT2EUL to be put in the model will be its inverse: S^-1
 
Finally, the sensing matrix LVDT2EUL we obtain is 
 
    0.6159   -0.5289   -0.0870
    0.2551    0.4058   -0.6610
    0.5612    0.5612    0.5612
 
(taking alpha = 22.5°  and R_h = 0.5940) 
 
Note that it is consistent with what Mark computed in its document T1807663-v1, if we take alpha = 30° instead of 22.5°.
    0.6159   -0.5289   -0.0870
    0.2551    0.4058   -0.6610
    0.5612    0.5612    0.5612
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